Sunday, September 18, 2011

Numerical Methods: Integration of given function using Simpson’s 1/3 rule in C

Source Code:

///integration of given function using Simpson's 1/3 rule
#include<stdio.h>
float y(float x){
    return 1/(1+x*x);
}
int main(){
    float x0,xn,h,s;
    int i,n;
    printf("Enter x0, xn, no. of subintervals: ");
    scanf("%f%f%d",&x0,&xn,&n);
    h = (xn - x0)/n;
    s = y(x0)+y(xn)+4*y(x0+h);
    for(i = 3; i<=n-1; i+=2){
        s += 4*y(x0+i*h) + 2*y(x0+(i-1)*h);
    }
    printf("Value of integral is %6.4f\n",(h/3)*s);
    return 0;
}

2 comments:

  1. this program is not correct -- for a correct solution use this link -- http://www.codewithc.com/c-program-for-simpson-1-3-rule/

    ReplyDelete
    Replies
    1. this is correct program

      Delete