Jogo simples de enforcamento em C++ [fechado]
oi então eu comecei c++ 3 dias atrás, ler alguns tutoriais etc. Eu queria fazer o meu próprio jogo de Carrasco já que parecia uma tarefa fácil para um mendigo, mas eu tropecei em um problema. Está tudo a funcionar bem, excepto que não consigo encontrar uma maneira de fazer uma troca de texto de 1 letra com sublinhados até que os sublinhados mudem para a palavra em falta. Então, basicamente, quando você compila, você pode adivinhar a palavra inteira apenas.
Aqui está o código:
#include <iostream>
#include <string>
using namespace std;
string player1,player2,word,underscore,guess;
int wrong=0;
int main (){
string copy = word;
cout << "----------------------Hello! Welcome to the HANGMAN game!---------- ----------" << endl;
cout << "Please type in your name, PLAYER 1" << endl;
cin >> player1;
cout << "Please type in your name, PLAYER 2" << endl;
cin >> player2;
cout << "OK " << player1 << " and " << player2 << ". Let's start with the game!" << endl;
cout << player1 << " please input the word you want " << player2 << " to guess." << endl;
cin >> word;
//space
for (int x=0; x<30; x++){
cout << endl;
}
//UNDERSCORE
while (underscore.size() != word.size()){
underscore.push_back('_');}
cout << underscore << endl;
//MAIN WHILE
while(wrong<12){
cin >> guess;
//IF GUESS ISNT LETTER
if(guess.size() > 1){
if(guess==word){
cout << "Thats the right word." << endl;
break;
}
else{
cout << underscore << endl;
cout << "Wrong word try again." << endl;
cout << "Used: " << usedguess << endl;
wrong ++;
}
}
if(underscore == word){
cout << "You win!" << endl;
break;
}
if(wrong==1){
cout << "I" << endl;
}
else if(wrong==2){
cout << "I" << endl;
cout << "I" << endl;
}
else if(wrong==3){
cout << "I" << endl;
cout << "I" << endl;
cout << "I" << endl;
}
else if(wrong==4){
cout << "I" << endl;
cout << "I" << endl;
cout << "I" << endl;
cout << "I" << endl;
}
else if(wrong==5){
cout << "I" << endl;
cout << "I" << endl;
cout << "I" << endl;
cout << "I" << endl;
cout << "I" << endl;
}
else if(wrong==6){
cout << "I===" << endl;
cout << "I" << endl;
cout << "I" << endl;
cout << "I" << endl;
cout << "I" << endl;
}
else if(wrong==7){
cout << "I===" << endl;
cout << "I O" << endl;
cout << "I" << endl;
cout << "I" << endl;
cout << "I" << endl;
}
else if(wrong==8){
cout << "I===" << endl;
cout << "I O" << endl;
cout << "I |" << endl;
cout << "I" << endl;
cout << "I" << endl;
}
else if(wrong==9){
cout << "I===" << endl;
cout << "I O" << endl;
cout << "I -|" << endl;
cout << "I" << endl;
cout << "I" << endl;
}
else if(wrong==10){
cout << "I===" << endl;
cout << "I O" << endl;
cout << "I -|-" << endl;
cout << "I" << endl;
cout << "I" << endl;
}
else if(wrong==11){
cout << "I===" << endl;
cout << "I O" << endl;
cout << "I -|-" << endl;
cout << "I /" << endl;
cout << "I" << endl;
}
else if(wrong==12){
cout << "I===" << endl;
cout << "I O" << endl;
cout << "I -|-" << endl;
cout << "I / /"<< endl;
cout << "I YOU ARE DEAD" << endl;
cout << "Game over bro! The word was: " << word <<endl;
break;
}
}
}
0
1 answers
Para comparar as cadeias de caracteres de word
e guess
, você pode iterar os caracteres num for-loop, e verificar se existe uma correspondência
string word = "hangman";
string guess = "mansomething";
string underscore = string(word.size(), '_'); // init a string with underscores equal to the length of 'word'
// iterate over the characters in word and guess
for (size_t i = 0, iend = min(word.size(), guess.size()); i < iend; i++) {
if (word[i] == guess[i])
underscore[i] = word[i]; // if the characters match at position i, update the underscore.
}
cout << underscore << endl;
Depois, underscore
contém o seguinte
_an____
1
Author: Morris Franken, 2015-12-04 15:45:24